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A semicircle and an interior circle are tangent to each other. The chord towards the tangency point is divided in segments of length 1 and 2. What is the pink area?

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## Solution

The pink area is (2-√3)(7π+3)/12, which is approximately 0,56.

The proof starts by using the fact that for interior touching circles, radii and chords are aligned. Therefore triangles GCE and GHB are similar and have length proportion 1 : 2. Thus the semicircle has three times the radius of the circle.

Now from the Inscribed angle theorem and from sin(2α)=1/2, we find that 2α=30°. Therefore β=150°.

Focussing on triangle GCE, it is straightforward to find that r=1/(2sin(75)). The pink area is a circular sector of 210° plus triangle GCE, which amounts to r2(21π/36+sin(150)/2). This can be worked out to the expression above.

## Poems

The sleeping baby
So tender in the night
The parents are caring
A nice song
I remember my childhood
Flashback to my past
And sorrows comforting
And a gently rocking cradle for a peaceful resting.

Bella

Day after day
Is coming the night.
While bells are ringing,
We’re on time and fight
Every day

Life is so good
But do run to fast.
While it’s so stunning,
Expect the forecast:
Sky will be good.

Gilles Pelletier

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