A point lies 8 from the centre of a circle of radius 6. The angle α is variable. What’s the maximum triangle area?

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## Solution

The maximum area is 14.

The area of the triangle is |PB|*|PC|*sin(2α)/2. Now because of reflection symmetry in the line through P and the circle centre, we see that |PB|=|PA|.

Next, we use the Power-of-a-point theorem, which says that |PA|*|PC|=8^{2}-6^{2}=28. So A(α)=14sin(2α). Clearly, this has a maximum of 14 at α=45°.