Hidden parallelogram

Blue circle (ACDGB) with CEG || AB. Pink circle (EDG) intersects AB at I. Extend DI to intersect blue circle at J, then JC intersects AB at M. Show that IM = CE.

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Solution

CEIM is parallelogram, ∴IM=CE

Blue circle (ACDGB) with CEG || AB. Pink circle (EDG) intersects AB at I. Extend DI to intersect blue circle at J, then JC intersects AB at M. Show that IM = CE. https://t.co/zD9veEcI3x By @MarshallWBuck pic.twitter.com/HIpjEOH84Y
— Mirangu (@Mirangu1) May 7, 2024

Solution

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