Blue circle (ACDGB) with CEG || AB. Pink circle (EDG) intersects AB at I. Extend DI to intersect blue circle at J, then JC intersects AB at M. Show that IM = CE.
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Solution
![](https://mirangu.com/wp-content/uploads/2024/05/HiddenParallelogramSolution.jpg)
CEIM is parallelogram, ∴IM=CE
Blue circle (ACDGB) with CEG || AB. Pink circle (EDG) intersects AB at I. Extend DI to intersect blue circle at J, then JC intersects AB at M. Show that IM = CE.
Scroll down for a solution to this problem.
CEIM is parallelogram, ∴IM=CE
Blue circle (ACDGB) with CEG || AB. Pink circle (EDG) intersects AB at I. Extend DI to intersect blue circle at J, then JC intersects AB at M. Show that IM = CE. https://t.co/zD9veEcI3x By @MarshallWBuck pic.twitter.com/HIpjEOH84Y
— Mirangu (@Mirangu1) May 7, 2024
One reply on “Hidden parallelogram”
I know.