Hidden parallelogram

Blue circle (ACDGB) with CEG || AB. Pink circle (EDG) intersects AB at I. Extend DI to intersect blue circle at J, then JC intersects AB at M. Show that IM = CE.

Scroll down for a solution to this problem.


Solution by yifs.

CEIM is parallelogram, ∴IM=CE

🤞 Don’t miss these puzzles!

Subscribe to the weekly geometry puzzle e-mail.

One reply on “Hidden parallelogram”

Leave a Reply

Your email address will not be published. Required fields are marked *

Optionally add an image (JPEG only)