Categories Beginner Decorating the tree Post author By Marshall W. Buck Post date December 19, 2023 1 Comment on Decorating the tree Decorating the tree A symmetric tree has decorative lines of equal slope, and of lengths 11 and 13. What is the area ratio of green to red to brown? Scroll down for a solution to this problem. Solution Green : red : brown is 1331 : 528 : 338. Solution by Stéphane Bernard. A symmetric tree has decorative lines of equal slope, and of lengths 11 and 13. What is the area ratio of green to red to brown? https://t.co/nEILpT3cRs By @MarshallWBuck pic.twitter.com/L8FK1hTocB— Mirangu (@Mirangu1) December 19, 2023 Please leave this field empty Don’t miss these puzzles! Subscribe to the weekly geometry puzzle e-mail. Email Address * Check your inbox or spam folder to confirm your subscription. Tags area, proportion, triangle ← The brick pile → Inside the box II One reply on “Decorating the tree” G=green area R=red area B= brown area G+R is similar to triangle G So G+R = (13/11)^2 G Also easy is (G+R+B)/(G+R)= 13/11. So G:G+R:G+R+B. = 11^3: 11*13^2: 13^3 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Email * Website Save my name, email, and website in this browser for the next time I comment. Δ Optionally add an image (JPEG only)
G=green area R=red area B= brown area G+R is similar to triangle G So G+R = (13/11)^2 G Also easy is (G+R+B)/(G+R)= 13/11. So G:G+R:G+R+B. = 11^3: 11*13^2: 13^3
One reply on “Decorating the tree”
G=green area
R=red area
B= brown area
G+R is similar to triangle G
So G+R = (13/11)^2 G
Also easy is (G+R+B)/(G+R)= 13/11.
So G:G+R:G+R+B. = 11^3: 11*13^2: 13^3